From 6ebf915691c15ace0faaed43d478c70b8d58b258 Mon Sep 17 00:00:00 2001 From: Kenichi Omichi Date: Fri, 9 Oct 2020 16:53:44 +0000 Subject: [PATCH] es: Fix output of 'kubectl rollout status' This is the same fix as https://github.com/kubernetes/website/commit/6e93717597113c726cbcf8a7059e47f23e3e8a64 for es. If running `kubectl rollout status` command, the output is like: ``` deployment "nginx-deployment" successfully rolled out ``` The corresponding kubectl code also shows it according to https://github.com/kubernetes/kubectl/blob/e95e378e5972064b177a8e71eac2803f55c8c5df/pkg/polymorphichelpers/rollout_status.go#L89 --- .../es/docs/concepts/workloads/controllers/deployment.md | 6 +++--- 1 file changed, 3 insertions(+), 3 deletions(-) diff --git a/content/es/docs/concepts/workloads/controllers/deployment.md b/content/es/docs/concepts/workloads/controllers/deployment.md index 89563b3b72..17a42882a0 100644 --- a/content/es/docs/concepts/workloads/controllers/deployment.md +++ b/content/es/docs/concepts/workloads/controllers/deployment.md @@ -109,7 +109,7 @@ Para ver el estado del Deployment, ejecuta el comando `kubectl rollout status de ```shell Waiting for rollout to finish: 2 out of 3 new replicas have been updated... -deployment.apps/nginx-deployment successfully rolled out +deployment "nginx-deployment" successfully rolled out ``` Ejecuta de nuevo el comando `kubectl get deployments` unos segundos más tarde: @@ -195,7 +195,7 @@ kubectl rollout status deployment.v1.apps/nginx-deployment ``` ``` Waiting for rollout to finish: 2 out of 3 new replicas have been updated... -deployment.apps/nginx-deployment successfully rolled out +deployment "nginx-deployment" successfully rolled out ``` Cuando el despliegue funciona, puede que quieras `obtener` el Deployment: @@ -803,7 +803,7 @@ kubectl rollout status deployment.v1.apps/nginx-deployment ``` ``` Waiting for rollout to finish: 2 of 3 updated replicas are available... -deployment.apps/nginx-deployment successfully rolled out +deployment "nginx-deployment" successfully rolled out $ echo $? 0 ```